If you meant you want to solve for c on: 5c-3 = 2c+6
you have to simplify the formula.
Step 1: Subtract 2c from both sides:
3c-3 = 6
Step 2: Add 3 to both sides
3c = 9
Step 3: Divide both sides by 3
c = 3
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2c + 3 = 15 Subtract 3 from both sides: 2c = 12 Divide both sides by 2: c = 6
Yes! So in conclusion, 1Q, 2C, and 1M are all equivalent. Goodbya, Koda! :P
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
An equation where c = 5