2c + 3 = 15 Subtract 3 from both sides: 2c = 12 Divide both sides by 2: c = 6
Yes! So in conclusion, 1Q, 2C, and 1M are all equivalent. Goodbya, Koda! :P
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
Without any information about a or b or c, all that can be said is: a + b + 2c = a + b + 2c Not particularly illuminating!
2c + 3 = 15 Subtract 3 from both sides: 2c = 12 Divide both sides by 2: c = 6
Yes! So in conclusion, 1Q, 2C, and 1M are all equivalent. Goodbya, Koda! :P
Well I got this: 2c+7=9+6-7c+2c 2c+7=15-9c 11c+7=15 (add 9c) 11c=8 ( Subtract 7) 11---11 ( Divide 11) C=0.72
-3.5. 2c would turn into -1.5 and seven wold turn to 3.5. add the two together and you get 2. 2+6=8 and you have your answer.
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
4c-7 = 2c+11 4c-2c = 11+7 2c = 18 c = 9
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
24c2 + 96c + 90 = 6*(4c2 + 16c + 15) = 6*(2c + 3)*(2c + 5)
Without any information about a or b or c, all that can be said is: a + b + 2c = a + b + 2c Not particularly illuminating!
An equation where c = 5
2c+(12-4)=20 Simplify the expression in the parentheses first. 2c+8=20 Subtract 8 from both sides of the equation. 2c=12 Divide both sides of the equation by 2. c=6
(b + 2c)(b - c)