It is: 6-11+5-8c+9c = c
Yes; the factored form would be (9c+4)(9c+4) or just (9c+4)2 Since the two factors are the same, the beginning trinomial 81c2+72c+16 is a perfect square trinomial
2ab - 6ac + 3b - 9c = b(2a + 3) - 3c(2a + 3) = (b - 3c)(2a + 3)
To find the product of 9c and 9e, you multiply the coefficients and the variables separately. The coefficients (9 and 9) multiply to give 81, and the variables (c and e) combine to give ce. Therefore, 9c x 9e equals 81ce.
The expression (9c \times 4e) represents the multiplication of two terms: (9c) and (4e). To multiply them, you multiply the coefficients (9 and 4) and then combine the variables. This results in (36ce). So, (9c \times 4e = 36ce).
To multiply (9c) by (9e), you multiply the coefficients (9 and 9) and then multiply the variables together. This results in (81ce). Therefore, (9c \times 9e = 81ce).
-6(a-3b-9c)
9c is.
(12c5 - 18c3 + 9c) / (-3c) = -4c4 + 6c2 - 3
3a + 9 =3X(a + 3)
Yes; the factored form would be (9c+4)(9c+4) or just (9c+4)2 Since the two factors are the same, the beginning trinomial 81c2+72c+16 is a perfect square trinomial
9
2ab - 6ac + 3b - 9c = b(2a + 3) - 3c(2a + 3) = (b - 3c)(2a + 3)
2ab - 6ac + 3b - 9c = 2a(b - 3c) + 3(b - 3c) = (2a + 3)(b - 3c).
Well I got this: 2c+7=9+6-7c+2c 2c+7=15-9c 11c+7=15 (add 9c) 11c=8 ( Subtract 7) 11---11 ( Divide 11) C=0.72
9C = 234
(2a + 3)(b - 3c)
18 degrees, C