c2+6c+9 = (c+3)(c+3)
It is:- 3c+5 = c+15 Subtact 5 and c from both sides: 2c = 10 Divide both sides by 2 to find the value of c: c = 5
14c + c + 12 = 15c + 12 = 3(5c + 4)
That's going to depend on the values of 'a', 'b', 'c', and 'f'.
C: there are no methods in C. C++: no.
The like terms are sums of b terms and c terms separately 5c+2c+3c+4b 5c +2c + 4b + 3c => 10c + 4b
(5c - 2)(c +1)
3c - 12 + 5c = 12Combine the 'c' terms on the left side:8c - 12 = 12Add 12 to each side:8c = 24Divide each side by 8:c = 3
The simplified answer is: 4c+2b
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
20c + 5 = 5c + 65 Divide through by 5: 4c + 1 = c + 13 Subtract c from both sides: 3c + 1 = 13 Subtract 1 from both sides: 3c = 12 Divide both sides by 3: c = 4 20c + 5 = 5c +65 20c - 5c= 65 - 5 15c = 60 15c/15 = 60/15 c = 4 (alternative method)
3c - 12 = 14 + 5cSubtract 3c from each side:-12 = 14 + 2cSubtract 14 from each side:-26 = 2cDivide each side by 2:-13 = c
3c
80°F = 262/3°C To convert Celsius to Fahrenheit, the formula is F = 9/5C + 32. If the Fahrenheit reading is 3 times the Celsius reading then F = 3C, so 3C = 9/5C + 32 : 6/5C = 32 : C = 262/3. Then F = 3C = 3 x 262/3 = 80
c=-7,c=-3,c=2,c=5
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
6c.