Its the nominal output of a electric charger required to run a certain device. The charger is designed to provide 9volts up to a current draw of .6 of an amp. The device it powers will need 9volts and a maximum current draw of .6 of an amp to charge/run it properly. Think of a water tank in a house being fed from the water main. The voltage is the head of water in the tank. Turn on the tap and the current is the rate of water flow. The water can only be supplied at a certain rate. Exceed the rate and the head of water (voltage) drops and needs to be replenished.
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this is an expression with a variable that is "v" 9v+74
the solution to the equation -53 plus 1 -26 is -78.
No, but sometimes "average" means "mean" - when it doesn't mean median, geometric mean, or something else entirely.
First of all you need to observe maximum current at various possible supply condition (i. e. 220VAC to 260VAC). Then check the inrush current for the equipment. When you start an high power device then it draws 4 times more current than usual. Your fuse should also take care of inrush current. For example: if maximum possible current is 500mA then your inrush current may go upto 2A. Thus if you put a fuse of 600mA then everytime you turn on the device, it may burn the fuse. So the suitable fuse for such condition is 2A
The answer will depend on who you mean by HE.The answer will depend on who you mean by HE.The answer will depend on who you mean by HE.The answer will depend on who you mean by HE.