It could be the length.
Surface area of any pyramid is 1/2Pl + B; where P=perimeter of the base, l=slant height and B= Area of the base.
a rectangular pyramid has a rectangular base and two pairs of congruent triangle sides. Given the height of the pyramid as well as its length and width, the area equals (l * w) + (l * (sq. rt ((w/2)^2 + h^2)) + (w * (sq. rt ((l/2)^2 + h^2)).
P*H+2*(L*B) Perimeter*Height+2*(lenght*Breadth)
To determine the surface area of a period (right rectangular), there is a unique formula. It is lw+l to the square root of w/2 squared + h squared + w square root of (l/2) squared + h squared. L=Length, W=Width, H=Height.
It could be the length.
SA = s2 + 2 × s × l
Surface area of any pyramid is 1/2Pl + B; where P=perimeter of the base, l=slant height and B= Area of the base.
Surface area of a triangular pyramid: SA = 1/2 as + 3/2 sl a = altitude of the base triangle s = side of the triangle l = slant height of the pyramid.
a rectangular pyramid has a rectangular base and two pairs of congruent triangle sides. Given the height of the pyramid as well as its length and width, the area equals (l * w) + (l * (sq. rt ((w/2)^2 + h^2)) + (w * (sq. rt ((l/2)^2 + h^2)).
P*H+2*(L*B) Perimeter*Height+2*(lenght*Breadth)
To determine the surface area of a period (right rectangular), there is a unique formula. It is lw+l to the square root of w/2 squared + h squared + w square root of (l/2) squared + h squared. L=Length, W=Width, H=Height.
Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl
The surface area is L*B where L is the length of the rectangle and B is the breadth.
"Surface area" is the covering of a multi-dimensional body. It is the area that the outside of a body has.For exampleA cube has a surface area of 6 * L2 where L is the length of one side. (six sides to the cube, each is a square with area L * L)
The question asks about the "pyramid shown". In those circumstances would it be too much to expect that you make sure that there is something that is shown?
If you assume that the all the sides are the same length l you can break it into two sections. the first, is the base which is a square which is Area = l.l the second is the equilateral triangle of side l, Area = l.l.sqrt(3)/4 So you have 4 triangles one square giving total surface area: l.l x (1 + sqrt(3) )