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How do I find the sum of 1 to 20?
The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210
What is this answer to Negative 17 equals 15 n minus 20?
If you mean -17 = 15n -20 then the value of n is 1/5
What is the answer to negative six n plus five equals one?
If you mean: -6n+5 = 1 then the value of n is 2/3
What number does n represent in maths?
n is a variable. It could mean any number you want it to. Most of the time, it is not specified what it is. Sometimes they give you clues about it, like "5 times n is 5." In this case n is 1.
The mean of n numbers is 5 If the number 13 is now included with the n numbers the new mean is 6 Find the value of n?
The mean of N numbers is the sum of those numbers divided by N. If you include 13 in that set and the new mean is 6, then the original N is 7. Let X be the original sum. You have a system of two simultaneous equations. 1.) X/N = 5 2.) X+13/N+1 = 6 To solve, substitute the value of X from eq. 1 into eq. 2 and then solve eq. 2 for N. (Some steps combined) X = 5N5N+13 = 6(N+1)5N = 6N-7-N = -7N = 7
GFEBS is a(n) initiative.?
Defense finance and accounting service
1 more than the quotient of 5 and n?
1 + 5/n
What is the geometric mean between 5 and 135?
geometric mean is: (5 x 135)1/2 = √675 ≈ 25.98 To find the geometric mean of n numbers, multiply them together and take the nth root, so the geometric mean of x1, x2, ..., xn is: geometric mean = (Π xr)1/n for r = 1, 2, .., n
What does corne mean?
1. aveia n.f.2. calo n.3. calosidade n.f.4. milho n.5. trigo n.
How do I find the sum of 1 to 20?
The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210
What is this answer to Negative 17 equals 15 n minus 20?
If you mean -17 = 15n -20 then the value of n is 1/5
What is the answer to negative six n plus five equals one?
If you mean: -6n+5 = 1 then the value of n is 2/3
What number does n represent in maths?
n is a variable. It could mean any number you want it to. Most of the time, it is not specified what it is. Sometimes they give you clues about it, like "5 times n is 5." In this case n is 1.
What is the answer to -1715n-20?
If you mean: -17 = 15n -20 then the value of n works out as 1/5
The mean of n numbers is 5 If the number 13 is now included with the n numbers the new mean is 6 Find the value of n?
The mean of N numbers is the sum of those numbers divided by N. If you include 13 in that set and the new mean is 6, then the original N is 7. Let X be the original sum. You have a system of two simultaneous equations. 1.) X/N = 5 2.) X+13/N+1 = 6 To solve, substitute the value of X from eq. 1 into eq. 2 and then solve eq. 2 for N. (Some steps combined) X = 5N5N+13 = 6(N+1)5N = 6N-7-N = -7N = 7
What is n 1 if n is 4?
if n=4 then n+1 would be 4+1 which equals 5
Any number to the zero power is equivalent to?
1proof:n**3 * n**-3 = n**0n**3 = n*n*nn**-3 = 1/n * 1/n * 1/n1/n * 1/n * 1/n * n * n * n= n*n*n/(n*n*n) = 1Any number to the zero power = 1 .Any number to the ' 1 ' power = itself .Also:ex. 3^0 = 1but this is also the same value as :5^0 = 1Hence 3^0 = 5^0 = n^0 = 1If you had 3^2 / 3^2 the result is 1 since any value divided by itself it 1.Hence the base (here it's 3) and the exponent (here it's 2) is essentially eliminated and the result is just 1 as it would be for any other base and exponent. Mathematically, in an expression form you can eliminate (set to 0) the exponent by subtracting the exponents:3^2 / 3^2 = 1 = 3^(2-2) = 3^0 = 1 = n^0X^0=1How about this:If you had 5^2 / 5^2 , it equal 1 since any number divided by that same value is one. Therefore there is no power of 5 left since 5^1 would be 5. It is as if you subracted the exponents: 5^(2-2) = 5^0. This is valid because if you had something like:5^2 / 5^1 = 5^(2-1) = 5^125 / 5 = 5 = 5^1
