Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
The formula is: (20-2)*180 = 3240 degrees which is the total sum of interior angles
Well, honey, the sum of counting numbers from 1 to 20 is 210. You add up 1 + 2 + 3... all the way to 20 and you get your answer. So, go ahead and impress your friends with your newfound math knowledge.
200, 20, 2, 0.2 Here you have 4 terms. Add them together, and you find the sum of these four terms. If you need to find the sum of some other terms, i.e 8 terms, then you can use the formula Sn = [a1(r^n - 1/(r - 1) where n = 8, a1 = 200, and r = 1/10.
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
Well, honey, the sum of counting numbers from 1 to 20 is 210. You add up 1 + 2 + 3... all the way to 20 and you get your answer. So, go ahead and impress your friends with your newfound math knowledge.
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
The sum of all integers from 1 to 20 inclusive is 210.
Factors for 20 are: 1, 2, 4, 5, 10, 20 Prime Factors: 2, 5 sum of prime factors = 2 + 5 = 7
Without just going and doing the addition, you can use this formula:Sum of 1 to N is: (N+1)*N/2. So take sum of [1 to 100], then subtract off the sum of [1 to 20], and you'll have left the sum [21 to 100].Sum [1-100] = (100+1)*100/2 = 5050. Sum[1-20] = (20+1)*20/2 = 210.So 5050 - 210 = 4840
Factors of 20 are 1, 2, 4, 5, 10 and 20. And their sum is 1 + 2 + 4 + 5 + 10 + 20 = 32.
The sum of the squares of the first 20 natural numbers 1 to 20 is 2,870.
Find the 2 numbers whose difference is two and whose sum is 480.
You find the sum of two numbers by adding the two together. Example: The sum of 1 + 1 is 2
the answer is 20-19=1
20