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What is the simplified answer to -n plus 4(n plus 1)?
-n + 4(n + 1) = 3n+4
What is the answer to n(n plus 1)?
n^2 + n
What is the answer to negative six n plus five equals one?
If you mean: -6n+5 = 1 then the value of n is 2/3
What does a plus n plus af plus mc plus cg equals af mean?
It means that a + n + mc + cg = 0
According to the Boolean algebra 1 plus A plus B plus C is equal to?
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
What is the formula for 1 plus 2 plus 3 plus 4 plus 5.?
If you mean the sum of first n natural numbers then the formula is (n(n+1))/2 for example, 1+2+3+4+5=5*6/2=15
Clara wrote 2 expressions 1 n equals 1 plus n 2 n equals 2 plus N?
2 plus n is the true one, but 1 plus n is not?
What is code of 1-2 plus 3-4 plus 5-6 plus ...n in c plus plus?
Did you mean 1-2+3-4+5-6....till n ?? If yes, then here it is: #include<iostream.h> void main() { int n,sum=0,check=1; cout<<"Enter n "; cin>>n; for(int i=1;i<=n;i++) { sum+=(check*i); check*=-1; } cout<<"The result of series is: "<<sum; }
What do these expressions have in common - n plus 2 n plus 3 n-1 n plus 6 n plus 10?
They have n in common.
Find the sum of 1 plus 2 plus 3 plus . plus n nos using c program?
if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;
What is the sum of 1 plus 2 plus 3 plus 4 plus 5. plus n?
(n2 + n)/2 1+2+3+4+5+n= 15+n
What is the sum of successor of n and predecessor of n is?
Successor of n=n+1 Predecessor of n=n-1 Sum=[n+1]+[n-1] Plus 1 plus minus 1= [1]+[-1]=0 [n][n] =2n Hope this helps
A class writes the equation n plus n plus 1 plus n plus 2 equals 87 to solve the following problem?
n = 28
What is 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7 plus 8 plus 9 plus 10 plus 11 plus 12 plus 13 plus 14 plus 15?
The sum of integers from 1 to n is n/2 times (n + 1), in this case 7.5 x 16= 120
What is n3 plus 1?
n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)
How do you solve 1 plus 2 plus plus 60?
If the question means solve 1+2+...+60 then 1+2+...+n = n(n+1)/2 for any integer n>0 So for n= 60 the sum is 60*61/2 = 30*61 = 1830
How do you mathematically express x equals n squared where it repeats until n equals 0 eg for n equals 4 x equals n squared plus n-1 squared plus n-2 squared plus n-3 squared?
Simple equation lad. In your example, you said n=4 and x= n squared + n - 1 + (n-2)squared + (n-3)squared. You simply write n²+n-1+(n-2)²+(n-3)² I hope that is what you mean by what you say. P.S. To get the to the power of sign, hold alt and press 0178 for ², and 0179 for ³
