On a practise test question, it says to calculate the value of the mean. I have no idea what it means because its a pretest. Can you please tell me???
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i want to calculate the percentage of mean value of particular data.
Deviations are calculated from some value: the mean, the median, the maximum or whatever. You subtract that value from each observed value.
A z-value by itself, has nothing to do with level of confidence.A z-value can be used to calculate probabilities of observing a result that is at least as far from the mean. That probability measure can be used to calculate the level of confidence but you need to be careful about using the one-tailed or two-tailed measures - as appropriate.A z-value by itself, has nothing to do with level of confidence.A z-value can be used to calculate probabilities of observing a result that is at least as far from the mean. That probability measure can be used to calculate the level of confidence but you need to be careful about using the one-tailed or two-tailed measures - as appropriate.A z-value by itself, has nothing to do with level of confidence.A z-value can be used to calculate probabilities of observing a result that is at least as far from the mean. That probability measure can be used to calculate the level of confidence but you need to be careful about using the one-tailed or two-tailed measures - as appropriate.A z-value by itself, has nothing to do with level of confidence.A z-value can be used to calculate probabilities of observing a result that is at least as far from the mean. That probability measure can be used to calculate the level of confidence but you need to be careful about using the one-tailed or two-tailed measures - as appropriate.
The first step is to find out what the deviation is from: the mean, median, some other fixed value. Whatever it is, call it m.For each observation x, calculate the absolute deviation, which is x - m or m - x, whichever is positive or zero. Finally, calculate the mean value (arithmetic average) of this set.
Suppose you have n observations {x1, x2, ... , xn} for a variable, X. Calculate m = (x1 + x2 + , ... , + xn)/n, the mean value. Calculate s2 = (x12 + x22 + , ... , + xn2)/n Then Variance = s2 - m2 = [mean of the squares] - [square of the mean] and the standard deviation = sqrt(Variance)