control+z = undo
It is 5x+y
(z + 15)(z + 3)
2z + 5 - xz
Ten z plus one, or ten z plus ten. That depends on where you had parentheses in the original expression: (10 * z) +1 = 10z + 110 * (z + 1) = 10z + 10
control+z = undo
Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
True
It is 5x+y
(z + 15)(z + 3)
10
2z + 5 - xz
x + y + z = x + z + y is the commutative property of addition.
Z + or - i and z-1
2z
z2
Ten z plus one, or ten z plus ten. That depends on where you had parentheses in the original expression: (10 * z) +1 = 10z + 110 * (z + 1) = 10z + 10