The last draw has no bearing on the next draw. Each draw is random.
12, 14, and 20 have an even number of factors. 4, 9, and 16 also have an even number of factors, but since they're perfect squares, two of the factors are the same number in each case, so each appears to have an odd number of factors.
Just one. Or, two if you count (1, p) and (p, 1) as being different.
Prime numbers have as factors the number 1 and their own number. Example: 37 is a prime number because its only factors are "1" and "37". If the prime number had further factors, it would no longer be prime.
Two numbers are factors of a product when they multiply with each other to become the product. For example, if the product number is 10, then our factors can be 2 and 5, or 1 and 10.
The Number of factors, (That is the number of pairs, such as 2= 1x2, 2x1), is equal to the number of rectangular arrays which can be made for each composite number. As such, the number of factors in the number 9 is 3, (1,3,9), and the number of rectangular arrays is also three (1x9, 9x1,3x3). Hope this helps!
Each factor pair is an array.
Records are distinguished from arrays by the fact that their number of fields is typically fixed, each field has a name, and that each field may have a different type.
I assume you mean that you have a number of rows, and that not all rows have the same number of "cells". Yes, in Java a two-dimensional array is implemented as an array of arrays (each item in the top-level array is, in itself, an array); a 3-dimensional array is an array of arrays of arrays, etc.; and there is no rule stating that all secondary (etc.) arrays must have the same number of elements.
identify two composite numbers that each have 8 as a factor
The last draw has no bearing on the next draw. Each draw is random.
You can make arrays with any number of dimensions (depending on RAM limitations, of course). However, internally, a two-dimensional array (for example) is stored as an array of arrays; that is, each first-level array contains an array of the second level. Similarly with higher dimensions.
1. List all factors of number (including 1 and the number, list each factor only once even if it goes in multiple times) 2. Add up all the factors 3. If the sum is equal to twice the original number, then the original number is perfect, if not, it is not perfect.
12, 14, and 20 have an even number of factors. 4, 9, and 16 also have an even number of factors, but since they're perfect squares, two of the factors are the same number in each case, so each appears to have an odd number of factors.
Just one. Or, two if you count (1, p) and (p, 1) as being different.
at least three factors.
do any number for the colums