Suppose we were considering the heights of all 18-year-old women in a certain European city. We might put the heights in a (long) list and sort them from smallest to largest.
Let's suppose that there were exactly 500 women on the list. 5% of them would be 25. The height of the woman at position 25 from the top would be called the 25th percentile. 95% would be 475, and the height of the woman at position 475 would be called the 95th percentile.
Then we might say that the 5th to the 95th percentile would include all the women from position 25 through position 475.
The 5th percentile is the value such that 5% of the population are below it. Similarly 50% or half the population lies below the 50th percentile.
The 50th percentile is average. The 5th is way below and the 95th is way above.The 5th and 95th percentiles are the lines that set of the "edges of the curve" in a distribution over a bell curve. If you draw the bell, and mark the 5th and 95th percentile spots, those marks separate the bulk of the curve from its edges. The 5th percentile sets off the bottom edge and the 95th percentile sets off the top edge of the curve.
The 5th percentile of a standard normal distribution is -1.645 (from the normal probability table). z = (x - μ) / σ -1.645 = (x-98.2) / .62 (0.62)(-1.645) = x-98.2 -1.0199 = x-98.2 x = 98.2-1.0199 = 97.1801 The 5th percentile is 97.18 The 95th percentile of a standard normal distribution is 1.645 (from the normal probability table). z = (x - μ) / σ 1.645 = (x-98.2) / .62 (0.62)(1.645) = x-98.2 1.0199 = x-98.2 x = 98.2+1.0199 = 99.2199 The 95th percentile is 99.22
It is the 31st percentile.
Mean.
The 5th percentile is the value such that 5% of the population are below it. Similarly 50% or half the population lies below the 50th percentile.
The 50th percentile is average. The 5th is way below and the 95th is way above.The 5th and 95th percentiles are the lines that set of the "edges of the curve" in a distribution over a bell curve. If you draw the bell, and mark the 5th and 95th percentile spots, those marks separate the bulk of the curve from its edges. The 5th percentile sets off the bottom edge and the 95th percentile sets off the top edge of the curve.
The 5th percentile of a standard normal distribution is -1.645 (from the normal probability table). z = (x - μ) / σ -1.645 = (x-98.2) / .62 (0.62)(-1.645) = x-98.2 -1.0199 = x-98.2 x = 98.2-1.0199 = 97.1801 The 5th percentile is 97.18 The 95th percentile of a standard normal distribution is 1.645 (from the normal probability table). z = (x - μ) / σ 1.645 = (x-98.2) / .62 (0.62)(1.645) = x-98.2 1.0199 = x-98.2 x = 98.2+1.0199 = 99.2199 The 95th percentile is 99.22
Yes, the mean (and median and mode) is the 50th percentile of any normal distribution.
It is the minimum value.
35% of values lie below the 35th percentile. The median (middle value) is the 50th percentile, 50% lie below it and 50% above.
A 99.6 percentile means that 99.6% of the data in the sample is at or below the data point given.
The 70th percentile is the score below which 70 percent of the cases fall. If your 70th percentile is 56, 70 percent of students scored below 56.
It is the 31st percentile.
Mean.
No, it is not.
it means that 33% of the people did not score that.