1 m/s² (1 metre per second per second) is a measure of acceleration, NOT speed. Assuming you mean a swim rate of 1.0 m/s (1 metre per second), then: time = distance ÷ speed = 900 m ÷ 1 m/s = 900 s 60 s = 1 min → 900 s = 900 ÷ 60 min = 15 minutes ---------------------------------- Assuming you really do mean that you swim with a constant acceleration of 1 m/s² and you start at 0 m/s, then: s = ut + ½at² s = 900 m u = 0 a = 1 m/s² t = unknown → 900 m = 0 m/s × t + ½ × 1 m/s² × t² → 900 m = ½t² → t² = 1800 s² → t ≈ 42.43 s If you start at 0 m/s and accelerate at 1 m/s², then it will take approx 42.43 seconds to cover 900 m.
Acceleration = (v - u)/t Replace each variable in the equation with their units Acceleration = (m/s - m/s) / s Same common denominator (m - m/s)/s Apply divison of fractions (m-m)/s*s (m/s^2) Note: I know m - m = 0 but they are just units expressing metres!
Vf = V0 + at --> 0 = (8.5 m/s) - (5.3 m/s²)t -> t = (8.5 m/s)/(5.3 m/s²) = 1.60377 s
total distance = 2m + 80m = 82 m total time = 2s + 40s = 42s → average speed = total distance / total time = 82m / 42s = 1 20/21 m/s ≈ 1.95 m/s
Given a random variable X with mean M and standard deviation S, Z = (X - M)/S
look up sadomasochism
It is a method used to set fitness targets, the goals will be s-specific M- Measureable A- Achieveable R- Realistic M- Time framed
S=Sado M=Masochism = sadomasochism
180 IS THE M S WITH 3 D
E= Early T= Time D= Dissmissal M= Monthly T= Time Y= Yesterday S=Study
0.034 m/s/s
1 m/s² (1 metre per second per second) is a measure of acceleration, NOT speed. Assuming you mean a swim rate of 1.0 m/s (1 metre per second), then: time = distance ÷ speed = 900 m ÷ 1 m/s = 900 s 60 s = 1 min → 900 s = 900 ÷ 60 min = 15 minutes ---------------------------------- Assuming you really do mean that you swim with a constant acceleration of 1 m/s² and you start at 0 m/s, then: s = ut + ½at² s = 900 m u = 0 a = 1 m/s² t = unknown → 900 m = 0 m/s × t + ½ × 1 m/s² × t² → 900 m = ½t² → t² = 1800 s² → t ≈ 42.43 s If you start at 0 m/s and accelerate at 1 m/s², then it will take approx 42.43 seconds to cover 900 m.
The change in velocity is 26 m/s - 12 m/s = 14 m/s. The time taken for this change is 6 seconds. Therefore, the average acceleration is (change in velocity / time) = 14 m/s / 6 s = 2.33 m/s^2.
Vi = 5 m/s A = (V_f- V_i )/t = (9 m⁄s- 5 m⁄s )/(4 sec) = (4 m⁄s )/(4 sec) = Vf = 9 m/s Change in time = 4 sec
Sexually Malested And Raped Twice S M A R T
S. M. James has written: 'Time in primary mathematics'
Acceleration = (v - u)/t Replace each variable in the equation with their units Acceleration = (m/s - m/s) / s Same common denominator (m - m/s)/s Apply divison of fractions (m-m)/s*s (m/s^2) Note: I know m - m = 0 but they are just units expressing metres!