if you have 12r and you minus 4r it doesn't equal 48. it would equal 8r to find out what r is i would have to see the whole problem
-1r
12r-20
12r + 4 = 112, 12r = 108, r = 9
r - 12 ≥ 5r - 12 + 12 ≥ 5 + 12r ≥ 17
if you have 12r and you minus 4r it doesn't equal 48. it would equal 8r to find out what r is i would have to see the whole problem
-1r
12r-20
12r + 4 = 112, 12r = 108, r = 9
It is 12r - 20 or 4*(3r - 5)
-6r-5 = 7-12r 12r-6r = 7+5 6r = 12 r = 2
r - 12 ≥ 5r - 12 + 12 ≥ 5 + 12r ≥ 17
That factors to 3(r - 5)(r + 1) r = 5, -1
(3r - 2)(3r - 2) or (3r - 2) squared.
12r - 20
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
The expression is: 12r-20 when simplified