That factors to 3(r - 5)(r + 1) r = 5, -1
(r + 9)(r + 3)
-1r
12r + 4 = 112, 12r = 108, r = 9
r^2 - 12r + 27 what two factors of 27 add up to - 12? (r - 3)(r - 9) FOIL that and get the quadratic polynomial back
That factors to 3(r - 5)(r + 1) r = 5, -1
(r + 9)(r + 3)
-1r
12r + 4 = 112, 12r = 108, r = 9
r^2 - 12r + 27 what two factors of 27 add up to - 12? (r - 3)(r - 9) FOIL that and get the quadratic polynomial back
12r - 15s - r + 3s = 11r -12s
- 6r - 5 = 7 - 12r add 12r to both sides 12r - 6r - 5 = 7 - 12r + 12r 6r - 5 = 7 add 5 to both sides 6r - 5 + 5 = 7 + 5 6r = 12 divide both side integers by 6 r = 2 ---------- check in original equation -6(2) - 5 = 7 - 12(2) - 12 - 5 = 7 - 24 - 17 = - 17 checks
Simplified its 12r+3s
if you have 12r and you minus 4r it doesn't equal 48. it would equal 8r to find out what r is i would have to see the whole problem
12r = p
12r - 20
12r-20