an angle subtended by an arc is double at the center
It will be the same angle subtended by its circumference.
An angle subtended at the semicircular arc is 90 degrees.
The question cannot be answered because it is not clear what is to be proved.
360 - 75 = 285
an angle subtended by an arc is double at the center
It will be the same angle subtended by its circumference.
An angle subtended at the semicircular arc is 90 degrees.
The question cannot be answered because it is not clear what is to be proved.
360 - 75 = 285
Let us recall the formula for the circumference of a circle. That one is 2pi r. r is the radius of the circle and 2pi is the angle in radian measure subtended by the entire circle at the centre. If this is so, then any arc length 'l' will be equal to the product of the angle in radian measure subtended by the arc at the centre and the radius.So l = theta r. Say theta is the angle subtended by the arc at the centre.Therefrom, r = l / Theta.
5.23
It depends on what measure you want: the angle subtended or the length of the curved segment, and also on what information you do have.
It is the subtended angle of the arc
May things, but the probable answer sought here is a diameter of a circle, at the circumference of the circle.
Full circumference of the circle = (2 pi) times (radius)Arc is a fraction of the full circumference.The fraction is (angle subtended at the center) divided by (360 degrees).If you have the radius 'R' and the angle 'A', the length of the arc is(pi) (R) (A) / 180
The angle subtended (on) a straight line is 180°. Two such angles = 2 x 180 = 360°.