tan(2x) = 2tanx/(1 - tan2x)
So tan(2x) +1 = 2tanx/(1 - tan2x) + 1
= 2tanx/(1 - tan2x) + (1 - tan2x)/(1 - tan2x)
= (-tan2x + 2tanx + 1)/(1 - tan2x)
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If y = 2x+1 is a tangent line to the circle 5y^2 +5x^2 = 1 then the point of contact is at (-2/5, 1/5) because it has equal roots
When you are using non-standard definitions of "plus" and "minus", or of "equal".
if the question u are asking is something like this 1/2 - ( - 1/2 ) then the answer is simple all you have to do is solve the equation like this 1/2 - ( - 1/2 ) = 1/2 + 1/2 = 2/2 = 1 its the - (-1/2) that is important remember the rule minus and minus equal plus plus and plus equal plus minus and plus equal minus remember and i hope it helps :)
1 + 1 = 2
2