To complete the square for the equation ( y = 4x^2 - 24x + 42 ), first factor out the 4 from the quadratic terms: ( y = 4(x^2 - 6x) + 42 ). Next, complete the square inside the parentheses by adding and subtracting ( 9 ) (which is ((\frac{6}{2})^2)): ( y = 4(x^2 - 6x + 9 - 9) + 42 ). This simplifies to ( y = 4((x - 3)^2 - 9) + 42 ), which further simplifies to ( y = 4(x - 3)^2 - 36 + 42 ), resulting in ( y = 4(x - 3)^2 + 6 ).
√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
The equation is : 24x + 6 = -5
The real equation got messed up when I posted it, the real equation is this: 2x^3 - 11x^2 + 24x - 18 divided by 2x - 3 ^ = to the 3rd and 2nd power.
33
x2 + 24x +180 = 0 By using the quadratic equation, you can find that x = -12 + 6i or x = -12 - 6i
The answer is, 24x
-45
By using the quadratic equation formula which will work out as: x = 4- the square root of 32 and x = 4+the square root of 32
2√6x
yes
√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
If you mean: y = 24x-15 then it is a straight line equation
The equation is : 24x + 6 = -5
The real equation got messed up when I posted it, the real equation is this: 2x^3 - 11x^2 + 24x - 18 divided by 2x - 3 ^ = to the 3rd and 2nd power.
33
x2 + 24x +180 = 0 By using the quadratic equation, you can find that x = -12 + 6i or x = -12 - 6i
false!