We would have to see the graph.
Yes it does.
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
A control limit on the graph for a process represents a point where the operator needs to take some predefined action.
The slope of the curve at each point on thegraph is the speed at that point in time. (Not velocity.)
A point can represent a piece of data or an (x,y) value.
We would have to see the graph.
The Orgin
The Orgin
manipulated variable
Yes it does.
Because each vertical lines meets its graph in a unique point.
pie graph
A-If there exists a vertical line that intersects the graph at exactly one point, the graph represents a function.B-If there exists a vertical line that intersects the graph at exactly one point, the graph does not represent a function. C-If there exists a vertical line that intersects the graph at more than one point, the graph represents a function.-DIf there exists a vertical line that intersects the graph at more than one point, the graph does not represent a function
instantaneous acceleration* * * * *No it does not.The graph is a distance-time graph so the coordinates of a point on the graph represent the position (distance) at the specified time. The gradient of the tangent to the curve at that point represents the instantaneous radial velocity. The second derivative at that point, if it exists, would represent the acceleration.
which is true about the functional relationship shown in the graph
A control limit on the graph for a process represents a point where the operator needs to take some predefined action.