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The force is up the slope and parralel to it, the load is essentially raised vertically.
It reduces the force needed to move the load up. Just think of it, it takes less force to push a cart with 100 kg of bricks on a slope or is it easier to lift it up directly to a height of 10m?
vertical lift versus slope the work done is the same (force * distance), but with a say 30 degree slope you need only half the force but need to travel twice as far to raise the load the same height vertically
No, Power factor may not have a magnitude greater than 1. It represents the proportion of power used by the load as compare to the total power delivered to the load. If the load is able to store power, then some of the power delivered to the load will be stored and then returned back to the electricity supply (50 times a second, depending on your grid frequency).
Hooke's Law tells use that a spring will deform linearly as y = m x + b were y is the length of the spring under loading m is the spring constant (slope of a line) b is the initial length of the spring first find the slope m: m = (y₂ - y₁) / (x₂ - x₁) m = (40 - 30) / (50 - 25) = 10 / 25 = 2/5 now use the point slope for the line equation and work to the slope intercept form y - y₁ = m(x - x₁) y - 30 = 2/5 (x - 25) y - 30 = 2/5x-10 y = 2/5x + 20 the spring is initially 20 cm long. ~I got this from another internet source, so i have no idea if this is right. but I'm pretty sure it is