I assume you are asking: z + 2 = 12
Then z would be 12-2=10
(z + 15)(z + 3)
x=3 y=2 z=6
To find a solution for the equation "what plus what divided by what equals 120," we can set it up as follows: Let ( x ) and ( y ) represent the two numbers being added, and ( z ) represent the number by which the sum is divided. One possible solution could be ( (x + y) / z = 120 ). For example, if ( x = 240 ), ( y = 0 ), and ( z = 2 ), then ( (240 + 0) / 2 = 120 ).
(2+x+y+6+z) += 9x,y and z are variables, there are 3.
y=84-72=12 z=84-52=32 x=84-12-32=40
10
(z + 15)(z + 3)
x=3 y=2 z=6
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
To find a solution for the equation "what plus what divided by what equals 120," we can set it up as follows: Let ( x ) and ( y ) represent the two numbers being added, and ( z ) represent the number by which the sum is divided. One possible solution could be ( (x + y) / z = 120 ). For example, if ( x = 240 ), ( y = 0 ), and ( z = 2 ), then ( (240 + 0) / 2 = 120 ).
z = -4 x-5 y+2
(2+x+y+6+z) += 9x,y and z are variables, there are 3.
y=84-72=12 z=84-52=32 x=84-12-32=40
-3y + z = 12
I used the matrix method to find the answer: x=4, y=-7, z=-5.
7 (seven)
12+1z