5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
(2, 1)
y=xsquared-4x+2
x + 5y = 10 5y = -x + 10 y = -x/5 + 2 m = -1/5 or .2
solv by cramr's rule [ 2x - 5y ] = 2 , [-4x + 10y ] = 1
(2, 2)
-2
(-1, 2)
X = -2(13 + y) / 3x = 5y / 4 - 1
4X - 5Y = - 2- 5Y = - 4X - 2Y = (4/5)X + 2/5m(slope) = 4/5==================
Multiply the first by 3 and the second by -2
Put in point slope form. Y =mX + c 4X + 5Y = - 10 5Y = - 4X - 10 Y = - (4/5)X - 2 =========== The slope(m) = - 4/5 --------------------------
-4x + 5y = 10Add 4x to each side:5y = 4x + 10Divide each side by 5:y = 0.8x + 2The graph of this equation is a straight line with [ slope = 0.8 ] and [ y-intercept = 2 ].
4x - 5y = -2 so 5y = 4x + 2 or y = 4/5x + 2/5 Now that it is in the standard form, the slope is the coefficint of x ie 4/5.
I think that wants to be 16x2 - 40xy + 25y2 That factors to (4x - 5y)(4x - 5y) or (4x - 5y)2
x = -1 and y = 2 The lines intersect at (-1, 2)
2