0
-- If the car is a hybrid or all-electric, then braking converts some of its kinetic energy
into some heat, which is dissipated into the air, and some electrical energy, which is
put back into the batteries.
-- If the car is the classic internal combustion type, then braking converts some of
its kinetic energy to all heat, which is dissipated into the air, and which can burn up
the brakes if it goes on for too long.
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How much energy does it take to stop a 3000 lb car traveling at 30 miles per hour?
Trick question--The answer is none. Indeed, energy in the form of heat is produced by the car stopping. But no energy is required to stop it. The brake pads, and drums or discs absorb energy and get hot.
A car traveling at 60 mph carries times the energy as the same car traveling 30 mph?
12
What has greater kinetic energy a car traveling at 35 miles per hour or a car traveling at 50 miles per hour?
Kinetic Energy is defined as the energy associated with motion. This is in contrast to potential energy which is associated with an entity's energy at rest, and it's potential for motion. Kinetic Energy can be calculated using this formula: KE = 0.5*Mass*Velocity^2, where KE = Kinetic Energy It is apparent by the formula that the same car traveling at a higher speed will have a greater kinetic energy than it does when traveling at a lower speed. Therefore, when the car travels at 50 mi/hr it has a higher kinetic energy than when it travels at 35 mi/hr. Let me just note that if we were talking about two different cars then we'd have to consider the weights of the cars.
Which has a greater kinetic energy a car traveling at 30 km h or a car half that mass traveling at 60 km h?
60. K= 1/2mv^2 therefore when v is larger, there is more kinetic energy
How many kilocalories of heat are generated when the brakes are used to bring a 960 kg car to rest from a speed of 101 km per hour?
((.5 * 960) * ((101 * 1 000 * 60 * 60)^2)) * 0.000239005736 = 1.5166917 × 1016 1/2 M V^2= kinetic energy times conversion from joules to kilocalories.
