To find two numbers that equal a sum of 7 and a difference of 1, let’s denote the numbers as ( x ) and ( y ). From the information given, we can set up the equations: ( x + y = 7 ) and ( x - y = 1 ). Solving these equations, we find that ( x = 4 ) and ( y = 3 ). Thus, the two numbers are 4 and 3.
The numbers are 7 and 6
The sum of 6 and 7 is found by adding the two numbers together, which equals 13. The product of 6 and 7 is found by multiplying the two numbers, which equals 42. Therefore, the difference between the two is 42 - 13 = 29.
the sum of six and one becuase that equals 7 and the product of six and one equals 6
If: 2x+8 = 7 then x = -1/2
The numbers 40.5 and 36.5 have a difference of 4 and a sum of 77.
The numbers are 7 and 6
7 is the product of the sum 16-9
The sum of 6 and 7 is found by adding the two numbers together, which equals 13. The product of 6 and 7 is found by multiplying the two numbers, which equals 42. Therefore, the difference between the two is 42 - 13 = 29.
the sum of six and one becuase that equals 7 and the product of six and one equals 6
six, seven 7 + 6 = 13 (sum) 7 - 6 = 1 (difference) 7 x 6 = 42 (product)
6 and 7
4*4=16 sum of 1+6 is 7, difference is 5 so 16 is answer
The product of 3 and 7 is found by multiplying the two numbers together, which equals 21. The sum of 3 and 7 is found by adding the two numbers together, which equals 10. Therefore, the difference between the product of 3 and 7 and the sum of 3 and 7 is 21 - 10 = 11.
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
7 + 4 = 11
If: 2x+8 = 7 then x = -1/2
5 x 7 and 6 x 7