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What line is Parallel to y-x 6 passing throuth 50?
Two lines are parallel if they have the same slope. First we need to find the slope m of the line with equation y - x = 6. So, y - x = 6 add x to both sides to turn the equation into the slope-intercept form y = x + 6 We know that the slope is the coefficient of the variable x, so the slope is 1. So the line that passes through (5,0) and parallel to the given line has also slope 1. Using the point (5, 0) = (x1, y1) and m = 1, we write the point-slope form of the equation of the required line, (y - y1) = m(x - x1) substitute the known values (y - 0) = 1(x - 5) y = x + 5 subtract x to both sides to turn this equation into the general form y - x = 5 Thus, the line that passes through (5,0) and parallel to the given line has the equation y - x = 5.
What is the slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (50) y 12 (-3)?
Without an equality sign and not knowing some of the plus or minus values of the given terms it can't be considered to be a straight line equation. But if you mean: y = 12x-3 a given point of (5, 0) Then the perpendicular equation is: y = -1/12x+5/12 whereas -1/12 is the slope and 5/12 is the y intercept
What is the slope of a line perpendicular to the graph of the equation below 2.1x - 5y equals 6.9?
Gradient of given line is 2.1/5 = 21/50 So gradient (slope) of perpendicular is -50/21 = -2.381 (to 3 dp)
Is this a linear equation 2L equals 100-2W?
Yes. This represents a line with a slope of 1 which intersects the axis at {l:50, w:0} and {l:0, w:50}
How do you graph y equals 40x plus 50?
The graph is a straight line, with a slope of 40, passing through the point y=50 on the y-axis.
