In order to solve for "L", you have to first tell me what "2L + 3" is. "2L + 3" is a number. What number it is depends on what "L" is. If I know what the number is, then I can solve for "L". There's no equation there, so nothing to solve.
If you would to solve for (l) then l = 4x/2 + 3/2 (4x + 3 is over 2).To solve for x. x = 2l/4 + 3/4 ( 2l + 3 is over 4)Hope this helps.
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
Do-it-in-your-head method: Half of 318 is 159, 159 minus 65 is 94 which is your answer, and not an equation in sight!Using the formulaThe formula for Perimeter is: P = 2L + 2W Knowing this, we can substitute and solve:318 = 2L + 2(65) (next simplify)318 = 2L + 130 (next subtract 130 form both sides of the equation)188 =2W (next divide both sides of the equation by 2)94 = WThe width of the rectangle is 94 yards.
2L is Bigger.
A little more info would be nice but as it stands your equation is 2L + C = P
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
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In order to solve for "L", you have to first tell me what "2L + 3" is. "2L + 3" is a number. What number it is depends on what "L" is. If I know what the number is, then I can solve for "L". There's no equation there, so nothing to solve.
The net ionic equation for the given reaction is: 2H+ + SO4^2- + Ca^2+ + 2I- → CaSO4(s) + 2H2O. This equation highlights the ions that participate in the reaction and the formation of the solid calcium sulfate and water.
If you would to solve for (l) then l = 4x/2 + 3/2 (4x + 3 is over 2).To solve for x. x = 2l/4 + 3/4 ( 2l + 3 is over 4)Hope this helps.
First, I am assuming you mean P = 2L + 2W, solve for W. If so, then see below! You solve equations the same way, whether they have multiple variables or not: Distribute, Combine Like Terms, Move the variable you are isolating to one side, Add or Subtract, then Multiply or Divide. Let's show how this equation is very much like an equation having only one variable: 28 = 20 + 2W -20 -20 8 = 2W ÷2 ÷2 4 = W So, if you get stuck, just "fake" the variables you aren't solving for into being random numbers. Solve your "fake" equation like you would any equation. Then use the same steps in your original "variable" equation. P = 2L + 2W -2L -2L P-2L= 2W ÷2 ÷2 (P-2L)/2 = W
2 L = 2000 mL1 L = 1000 mL
The net ionic equation of the reaction given is: 2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺(aq) + 2I⁻(aq).
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
P = perimeter, W = width, L = length P = 2(W + L) = 2W + 2L 2L = P - 2W L = P/2 - W