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What 2l plus 3 solveing for l?
In order to solve for "L", you have to first tell me what "2L + 3" is. "2L + 3" is a number. What number it is depends on what "L" is. If I know what the number is, then I can solve for "L". There's no equation there, so nothing to solve.
If 4x plus 2l plus 6 equals 3 show that l equals 13-2x?
If you would to solve for (l) then l = 4x/2 + 3/2 (4x + 3 is over 2).To solve for x. x = 2l/4 + 3/4 ( 2l + 3 is over 4)Hope this helps.
What eqations represents the formula for perimiter of a rectangle p equals 2l plus 2w solve for l?
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
The perimeter of a rectangular field is 318 yards. If the width of the field is 65 yards what is its length?
Do-it-in-your-head method: Half of 318 is 159, 159 minus 65 is 94 which is your answer, and not an equation in sight!Using the formulaThe formula for Perimeter is: P = 2L + 2W Knowing this, we can substitute and solve:318 = 2L + 2(65) (next simplify)318 = 2L + 130 (next subtract 130 form both sides of the equation)188 =2W (next divide both sides of the equation by 2)94 = WThe width of the rectangle is 94 yards.
What is the net ionic equation oh 2H plus plus SO4- plus CA2 plus plus 2l- CaSO4 plus 2H plus 2l-?
To derive the net ionic equation, we first identify the species involved in the reaction. The complete ionic equation shows that we have 2 H⁺ ions, 1 SO₄²⁻ ion, 1 Ca²⁺ ion, and 2 I⁻ ions. When calcium sulfate (CaSO₄) forms, the net ionic equation simplifies to: Ca²⁺ + SO₄²⁻ → CaSO₄(s). The H⁺ and I⁻ ions are spectator ions and do not appear in the net ionic equation.
What is L plus L plus C equals P?
A little more info would be nice but as it stands your equation is 2L + C = P
If P equals 2L - 2W solve for L if P equals 40 and W equals 2?
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What 2l plus 3 solveing for l?
In order to solve for "L", you have to first tell me what "2L + 3" is. "2L + 3" is a number. What number it is depends on what "L" is. If I know what the number is, then I can solve for "L". There's no equation there, so nothing to solve.
What is the net ionic equation of 2H SO422- Ca 2l CaSO4 2H 2l?
The net ionic equation for the given reaction is: 2H+ + SO4^2- + Ca^2+ + 2I- → CaSO4(s) + 2H2O. This equation highlights the ions that participate in the reaction and the formation of the solid calcium sulfate and water.
If 4x plus 2l plus 6 equals 3 show that l equals 13-2x?
If you would to solve for (l) then l = 4x/2 + 3/2 (4x + 3 is over 2).To solve for x. x = 2l/4 + 3/4 ( 2l + 3 is over 4)Hope this helps.
How do you solve questions like P2L 2W solve for W?
First, I am assuming you mean P = 2L + 2W, solve for W. If so, then see below! You solve equations the same way, whether they have multiple variables or not: Distribute, Combine Like Terms, Move the variable you are isolating to one side, Add or Subtract, then Multiply or Divide. Let's show how this equation is very much like an equation having only one variable: 28 = 20 + 2W -20 -20 8 = 2W ÷2 ÷2 4 = W So, if you get stuck, just "fake" the variables you aren't solving for into being random numbers. Solve your "fake" equation like you would any equation. Then use the same steps in your original "variable" equation. P = 2L + 2W -2L -2L P-2L= 2W ÷2 ÷2 (P-2L)/2 = W
How many milliliter equals to 2L?
2 L = 2000 mL1 L = 1000 mL
Solve for w 2l plus 2w equals P?
Oh honey, solving for w in 2l + 2w = P is as easy as stealing candy from a baby. Just subtract 2l from both sides and then divide by 2. Voila, w = (P - 2l) / 2. Now go show off your math skills like the boss you are.
What is the net ionic equation of 2H SO4 2 Ca2 2l- CaSO4 2H 2l-?
Ca2+(aq) + SO42-(aq)- --> CaSO4(s) is the net ionic equation.
The length of rectangle is 5 less than twice the width The perimeter of the rectangle is 80. Find the dimensions of the rectangle?
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
What eqations represents the formula for perimiter of a rectangle p equals 2l plus 2w solve for l?
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
How do you write an equation when the perimeter and width are known but the length is needed?
P = perimeter, W = width, L = length P = 2(W + L) = 2W + 2L 2L = P - 2W L = P/2 - W
