-7 therefore the quadratic equation has no real roots
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
2x2 + 3x - 20 = (x + 4)(2x - 5).
It is a quadratic equation that has 2 solutions
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
-7 therefore the quadratic equation has no real roots
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
2x2 + 3x - 20 = (x + 4)(2x - 5).
It is a quadratic equation that has 2 solutions
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
There are no solutions to this quadratic equation because the discriminant is less than zero.
If it was expressed as a quadratic equation it would have no roots because the discriminant is less than zero
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
There are no powers e.g 2x2 would be due to the 2
6.50 to the nearest hundredth (4.685 & 1.815)
None because the discriminant of this quadratic equation is less than zero.