-7 therefore the quadratic equation has no real roots
-7
The discriminant is -7
2X2+5x-12 4+5x-12 -8+5x 5x-8
D = b²-4ac a=2, b=5, c=4 D=5²-4(2*4) D=25-4(8) D=25-32 D=-7■
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
-7
Discriminant = 52 - 4 x 2 x (-8) = 89
The discriminant is -7
2X2+5x-12 4+5x-12 -8+5x 5x-8
2x^(2) - 5x - 12 First write down all the factors of '2' & '12' 2 = 1,2 12 = 1,12; 2,6; 3,4 . From this we select two pairs of numbers, one pair from each coefficient, that add/multiply to '5' They are, 1,2 & 3,4 Hence -(2 x 4) + (1 x 3) = -8 + 3 = -5 Set up the brackets (2x 3)(x 4) Hence the signs are ( 2x + 3)(x - 4)
-7
D = b²-4ac a=2, b=5, c=4 D=5²-4(2*4) D=25-4(8) D=25-32 D=-7■
It is: 25-4(8*6) = -167
The discriminant is 9.
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
52-4*7*1 = -3 The discriminant is less than zero so the quadratic equation will have no solutions.