Q: What expression describe the length of the rectangle the length of the rectangle is 84.5 square centimeter?

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The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.

The perimeter of a rectangle is equal to twice the length plus twice the width, so P = 2l + 2w P = (2x25) + (2x13) P = 50 + 26 P = 76 centimeters

Use Pythagoras' theorem: 62+32 = 45 and the square root of 45 is about 6.708203932 cm

I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.

Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.

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150cm.

The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.

Area=Length X Width

We can use either meter or centimeter to measure a rectangle. For a large area of rectangle we can also use "feet" or " yards". Using "meter" is a convenient form to measure the length of the rectangle.

15 (it is actually really close to 15 and a half)

The perimeter of a rectangle is equal to twice the length plus twice the width, so P = 2l + 2w P = (2x25) + (2x13) P = 50 + 26 P = 76 centimeters

Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.

Use Pythagoras' theorem: 62+32 = 45 and the square root of 45 is about 6.708203932 cm

Doesn't describe the problem well enough.

I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.

Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.

To find the area of a rectangle, you multiply the length by the width (one side by a different side) Or you could count how many centimeter squares make up the rectangle