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What is the width of the rectangle if the length is 7.5 centimeters and the perimeter is 38?
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
What is the width of a rectangle that has a length of7.5 and a perimeter of38?
It is: 11.5 Check: 2*(7.5+11.5) = 38
If the Perimeter of the rectangle is 38 inches the length is 3 inches more find the width?
The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38
A rectangle has a perimeter of 38 cm and an area of 60 m squared what is the length and width?
This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
