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What is the width of the rectangle if the length is 7.5 centimeters and the perimeter is 38?
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
What is the width of a rectangle that has a length of7.5 and a perimeter of38?
It is: 11.5 Check: 2*(7.5+11.5) = 38
If the Perimeter of the rectangle is 38 inches the length is 3 inches more find the width?
The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38
A rectangle has a perimeter of 38 cm and an area of 60 m squared what is the length and width?
This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.
When the perimiter of the rectangle is 38 inches If the rectangle is less than 4 times the width find the area of the rectangle Confused how to do this?
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
What is the area of a rectangle that has a length of 38 and a width of 28?
Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.
A rectangle has a length of 11 feet and a perimeter of 38 feet. What is the width in feet of the rectangle?
The width is 8 feet
What is the perimeter of a rectangle with a length of 11 and a width of 8?
The perimeter is 38.
If the perimeter of a rectangle is 38 centimeters and the length is 7.5 centimeters What is the width?
9 cm
The length of a rectangle is five feet more than twice its width and the area of the rectangle is sixty-three Find the dimensions of the rectangle?
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
What is the width of the rectangle if the length is 7.5 centimeters and the perimeter is 38?
Perimeter = 2(Length + Width)38 = 2*(7.5 + W)38 = 15 + 2W so 2W = 23 so that W = 11.5 cmA peculiar result since normally the length is larger than the width.
What is the width of a rectangle that has a length of7.5 and a perimeter of38?
It is: 11.5 Check: 2*(7.5+11.5) = 38
What is the length of a rectangle that has a perimeter of 108 feet the length is twice the width plus 6 feet what is the length?
P = 2L + 2WL = 2W + 62L = 4W + 12108 = 6W + 126W = 96W = 16L = 38 feet38 + 38 + 16 + 16 = 108
If the Perimeter of the rectangle is 38 inches the length is 3 inches more find the width?
The formula for the perimeter of a rectangle is P=2(l + w). You know that the length is 3" more than the width. Hence you could substitute x for the width and x+3 for the length and use the formula to solve for the width: P = 2(l + w) 38 = 2(x + 3 + x) 38 = 4x + 6 32 = 4x 8 = x Hence, the width is 8" and the length is 11" Proof: P = 2(11 + 8) P = 2(19) P = 38
What is the perimeter of a rectangle with a length of 11inches and a width of 8 inches?
Perimeter = 11+11+8+8 = 38 inches
What is the length and width of 38 square meters?
To determine the length and width of a 38 square meter area, we need more information as there are infinite possibilities. However, if we assume the area is a rectangle, we can find the dimensions by factoring 38 into pairs of numbers (1x38, 2x19, etc.) and then calculate the length and width. It's important to note that there are multiple combinations of length and width that can result in a total area of 38 square meters.
A rectangle has a perimeter of 38 cm and an area of 60 m squared what is the length and width?
This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.
