You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.
What is 3x-6y=12
5/4
It is a linear relationship between x and y.
yes, change in y over change in x equals slope
x = yz/(y - z)
y is directly proportional to x. When y = 15, x = 3 therefore y = 5x When x = 12, then y = 5 x 12 = 60.
It equals n(x+y) / x*y.
What is 3x-6y=12
5/4
It is a linear relationship between x and y.
yes, change in y over change in x equals slope
T/y = x/wMultiply each side by 'x':Tw/y = x
x = yz/(y - z)
x=4, y=3
If y(x) = 1/3x, y(-18) = 1/[3(-18)] = -1/54.
No, it is not.
The lines are mutually perpendicular.