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How do you convert the square root of x into an expression?
Write it as sqrt(x) or x1/2 or x0.5
When will you say that Algebraic Expression is not Polynomial?
When it has any term in which the variable is not raised to a non-nagative integer power. So for example, if it contains a term such as x-3 [the power is not positive] or x1/2 or sqrt(x) [the power is not an integer] or sin(x), or log(x) etc [not powers of x].
How do you solve x2 equals cos x?
You can solve this to the accuracy of your liking by using Newton's method: xn+1 = xn - f(xn) / f'(xn) In this case, we'll say f(x) = x2 - cos(x) f'(x) would then be 2x + sin(x) Let's take a rough guess, and start with x0 = 0.5 x1 = 0.5 - (0.52 - cos(0.5)) / (2(0.5) + sin(0.5)) = 0.92420692729319751536 x2 = x1 - (x12 - cos(x1)) / (2x1 + sin(x1)) = 0.82910575599741780916 x3 = x2 - (x22 - cos(x2)) / (2x2 + sin(x2)) = 0.82414613172819520712 x4 = x3 - (x32 - cos(x3)) / (2x3 + sin(x3)) = 0.8241323124099124229 x5 = x4 - (x42 - cos(x4)) / (2x4 + sin(x4)) = 0.82413231230252242297 x6 = x5 - (x52 - cos(x5)) / (2x5 + sin(x5)) = 0.82413231230252242296 Now we can test our answer: 0.824132312302522422962 = 0.67919406818110235182 cos(0.82413231230252242296) = 0.67919406818110235183 So we're accurate to the nearest ten quintillionth.
What is the period for sine?
Periodic functions are those functions for which the value of the dependent variable repeats itself for certain values of the dependent variable.example:F(x)=yx is the dependent variable (output of the function)y is the independent variable (input of the function)F(x1)=y1F(x2)=y1As you can see the value of the function is the same for two different values of the dependent variable.The smallest difference between any two dependent variables giving the same value of the function is the period of the function.The periodicity of the usual sine function is 2pi. This is how it works:F(X)=sin(X)sin(x1)=ysin(x2)=sin(x1+2pi)=ysin(x3)=sin(x1+4pi)=yThe smallest difference between any two independent variables (x1 or x2 or x3) is 2pi.This is also evident from the general sine curve (graphical representation). The sine function has a fixed range from -1 to 1 (i.e.,for sin(x)=y, y can only lie between -1 and 1). So, the interval (difference in values of the independent variable) after which the nature of the wave repeats is it's period. Look at the graph and you'll see that the wave replicates after covering 2pi from the current point.
What the usual period for sine?
Periodic functions are those functions for which the value of the dependent variable repeats itself for certain values of the dependent variable.example:F(x)=yx is the dependent variable (output of the function)y is the independent variable (input of the function)F(x1)=y1F(x2)=y1As you can see the value of the function is the same for two different values of the dependent variable.The smallest difference between any two dependent variables giving the same value of the function is the period of the function.The periodicity of the usual sine function is 2pi. This is how it works:F(X)=sin(X)sin(x1)=ysin(x2)=sin(x1+2pi)=ysin(x3)=sin(x1+4pi)=yThe smallest difference between any two independent variables (x1 or x2 or x3) is 2pi.This is also evident from the general sine curve (graphical representation). The sine function has a fixed range from -1 to 1 (i.e.,for sin(x)=y, y can only lie between -1 and 1). So, the interval (difference in values of the independent variable) after which the nature of the wave repeats is it's period. Look at the graph and you'll see that the wave replicates after covering 2pi from the current point.
State the principle of duality of Boolean algebraBoolean?
Principle of Duality helps us to find the possible correct boolean expression. "Any theorem or identity in switching algebra remains true if 0 and 1 are swapped and . and + are swapped." Mathematically f(x1,x2,...,xn,.,+,1,0)=f(x1,x2,...,xn,+,.,0,1) Important point to note is that dual of expression different from the complement of expression. Mathematically f(x1,x2,...,xn,.,+,1,0)=f(x1`,x2`,...,xn`,+,.,0,1); i.e. if x1 belongs to positive logic then x1` denotes the negative logic and vice versa. De-morgans law is helps us to obtain the complement of expression.
When using the slope formula does it have to be (y2-y1)(x2-x1) or can it be (y1-y2)(x1-x2)?
If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.
How do you convert the square root of x into an expression?
Write it as sqrt(x) or x1/2 or x0.5
How do you write an expression in radical form?
Re-write it with a root. If the power of the expression is less than 1, for example x1/3, the expression could be rewritten as cube root of x.
How do you differentiate sin rootx?
By the chain rule, the derivative of sin(x1/2) will be the derivative of x1/2 multiplied by the derivative of the enclosing sine function. Thus, y = sin(x1/2) y' = (1/2)*(x-1/2)*cos(x1/2) For further reading, you might want to consult your calculus book on the chain rule. Here is a site that (kind of) explains the chain rule, though it does have good examples: http://archives.math.utk.edu/visual.calculus/2/chain_rule.4/index.html For step-by-step derivatives of functions, try Calc 101: http://calc101.com/webMathematica/derivatives.jsp
Explain how to find the distance between the points (28 -17) and (-15-17) on a coordinate plane?
To find the distance between any two points on the Cartesian plane use Pythagoras: The distance between (x0, y0) and (x1, y1) is given by: distance = √((x1 - x0)² + (y1 - y0)²) → distance between (28, -17) and (-15, -17) is: distance = √((x1 - x0)² + (y1 - y0)²) = √((-15 - 28)² + (-17 - -17)²) = √((-43)² + (0)) = √1849 = 43 ------------------------ In this case, the y-coordinates are the same (y0 = y1 = -17), so this becomes: distance = √((x1 - x0)² + (y0 - y0)²) = √((x1 - x0)² + 0²) = √((x1 - x0)²) = |x1 - x0| The vertical bars around the expression mean the absolute value of the expression, which is the numerical value of the expression ignoring the sign. distance = |x1 - x0| = |-15 - 28| = |-43| = 43.
Integral of sin square root x?
For ∫ sin(√x) dx let y = √x = x1/2 → dy = 1/2 x-1/2 dx → 2x1/2 dy = dx → 2y dy = dx → ∫ sin(x1/2) dx = ∫(sin y) 2y dy Now: ∫ uv dx = u∫v dx - ∫(u'∫v dx) dx → ∫(sin y) 2y dy = ∫2y sin y dy = 2y ∫sin y dy - ∫(2 ∫sin y dy) dy = -2y cos y + 2 sin y + C = 2 sin y - 2y cos y + C → ∫ sin(√x) dx = 2 sin(√x) - 2(√x) cos(√x) + C
When will you say that Algebraic Expression is not Polynomial?
When it has any term in which the variable is not raised to a non-nagative integer power. So for example, if it contains a term such as x-3 [the power is not positive] or x1/2 or sqrt(x) [the power is not an integer] or sin(x), or log(x) etc [not powers of x].
How do you solve x2 equals cos x?
You can solve this to the accuracy of your liking by using Newton's method: xn+1 = xn - f(xn) / f'(xn) In this case, we'll say f(x) = x2 - cos(x) f'(x) would then be 2x + sin(x) Let's take a rough guess, and start with x0 = 0.5 x1 = 0.5 - (0.52 - cos(0.5)) / (2(0.5) + sin(0.5)) = 0.92420692729319751536 x2 = x1 - (x12 - cos(x1)) / (2x1 + sin(x1)) = 0.82910575599741780916 x3 = x2 - (x22 - cos(x2)) / (2x2 + sin(x2)) = 0.82414613172819520712 x4 = x3 - (x32 - cos(x3)) / (2x3 + sin(x3)) = 0.8241323124099124229 x5 = x4 - (x42 - cos(x4)) / (2x4 + sin(x4)) = 0.82413231230252242297 x6 = x5 - (x52 - cos(x5)) / (2x5 + sin(x5)) = 0.82413231230252242296 Now we can test our answer: 0.824132312302522422962 = 0.67919406818110235182 cos(0.82413231230252242296) = 0.67919406818110235183 So we're accurate to the nearest ten quintillionth.
What are the Pokemon types of the elite 4 in Pokemon pearl?
Aaron Poison/Bug x1 Bug/Fighting x1 Bug/Flying x2 Poison/Dark x1 Bertha Water/Ground x2 Ground x1 Rock x1 Rock/Ground x1 Flint Fire x1 Fire/Fighting x1 Steel/Ground x1 Normal x1 Ghost/Flying x1 Lucian Psychic x2 Normal/Psychic x1 Fight/Psychic x1 Steel/Psychic x1 Cynthia Ghost/Dark x1 Dragon/Ground x1 Water/Ground x1 Water x1 Grass/Poison x1 Steel/Fighting x1
Can you fix or rate my dragon deck?
decklist monsters:21 blue eyes white dragon x3 chaos necromancer x1 masked dragon x1 armed dragon lvl3 x2 armed dragon lvl5 x2 armed dragon lvl7 x1 armed dragon lvl10 x1 the dragon dwelling in the cave x1 flamvell guard x1 lord of d x1 vangaurd of the dragon x1 the white stone of legend x1 kaiser sea horse x1 montage dragon x1 mirage dragon x1 tyrant dragon x1 blue eyes shining dragon x1 spell cards:15 flute of summoning dragon x1 polermyzation x2 monster reborn x1 magical mallet x1 stamping destruction x2 dragons mirror x1 deifferent dimension capsule x2 dark hole x1 future fusion x1 white dragon ritual x1 swords of revealing light x1 mystical space typhoon x1 traps:10 dragons rage x1 waboku x1 enchanted javelin x1 judgment of Anubis x1 call of the haunted x1 acid trap hole x1 hidden book of spell x1 raigeki break x1 curse of Anubis x1 self destruction button x1 (hoping i wont need that anymore) extra deck:2 paladin of white dragon x1 blue eyes ultimate dragon x1
What is the best dragon Yu-Gi-Oh deck that is tournament legal?
Mine is: Blizzard Dragon X2 Ryu Kushin Powered X1 Baby Dragon X3 Time Wizard X4 Manga Ryu-Ran X1 Ryu-Ran X1 Armored Lizard X1 Influence Dragon X1 Powered Tuner X2 InterPlanetPurplyThorny Dragon X2 Hieratic Dragon of Eset X1 Light And Darkness Dragon X1 Lord Of D. X1 Koumori Dragon X1 Curse Of Dragon X1 Dragon Of Ice X2 The Dragon Dwelling In the Cave X2 Lava Dragon X1 Two Headed Behemoth X1 Dragunity Arma Mystletainn X1 Hieratic Dragon Of Nebthet X1 Ancient Dragon X1 Dragon Zombie X1 Mirage Dragon X1 Bright Star Dragon X1 Dark Blade X1 Pitch Dark Dragon X1 (I actually have the cards below) MALEFIC CYBER END DRAGON X1 Slifer The Sky Dragon X2 Magic & Traps Card DesctructionX1 Double Summon X1 Gracious Charity X1 Frontline Base X1 reversal quiz X2 MetaSilver Armor X1 Dian Keto The Cure Master X1 Poison Of the old man X1 Dragon Mastery x1 Dragon treasure x1 Fusion Gate x1 change of heart x1
