The expression equivalent to log (92) is the exponent to which the base (usually 10 or e) must be raised to obtain the number 92. In other words, log (92) is the power to which the base must be raised to get 92. The specific value of log (92) depends on the base used in the logarithmic expression.
34 is an equivalent expression.
2*log(15) = log(x) 152 = x; its equivalent logarithmic form is 2 = log15 x (exponents are logarithms) then, it is equivalent to 2log 15 = log x, equivalent to log 152 = log x (the power rule), ... 2 = log15 x 2 = log x/log 15 (using the change-base property) 2log 15 = log x Thus, we can say that 152 = x is equivalent to 2*log(15) = log(x) (equivalents to equivalents are equivalent)
It is the expression -2m + 92. This cannot be evaluated without knowing the value of m.
the length of time that is equivalent to 92 hours is 5,500 min
3.092 is equivalent to 3.0920
log(100x) can be written as log100 + logx. This =2+logx
log4+log3=log(4x3)=log12
34 is an equivalent expression.
The expression x = log3(100) is equivalent to 3x = 100. One way to calculate logs with a base of (b) is: logb(y) = log(y) / log(b). So in this case, you would have log(100) / log(3) = 4.192 [rounded to 3 decimal places]
The expression 9+5 is equivalent.
2*log(15) = log(x) 152 = x; its equivalent logarithmic form is 2 = log15 x (exponents are logarithms) then, it is equivalent to 2log 15 = log x, equivalent to log 152 = log x (the power rule), ... 2 = log15 x 2 = log x/log 15 (using the change-base property) 2log 15 = log x Thus, we can say that 152 = x is equivalent to 2*log(15) = log(x) (equivalents to equivalents are equivalent)
It is the expression -2m + 92. This cannot be evaluated without knowing the value of m.
the length of time that is equivalent to 92 hours is 5,500 min
92%= 0.92 in decimal= 92/100 or 23/25 in fraction
If an algebraic expression is equivalent to another algebraic expression then it is an equation.
18 and 2/5 or 92/5
92%= 0.92 in decimal= 92/100 or 23/25 in fraction