57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
No.
No.
Any of its multiples! Simply calculate any of the following: 57 x 0 57 x 1 57 x 2 57 x 3 57 x (-1) 57 x (-2) etc., and you get a number that is a multiple of 57, and therefore, divisible by 57.
Sadly, it is not.
The factors of 27 are: 1, 3, 9, 27 The factors of 57 are: 1, 3, 19, 57 The factors of 97 are: 1, 97 The factors of 98 are: 1, 2, 7, 14, 49, 98
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
No. 57 is divisible by 3.
1, 3, 19, 57.
57 is divisible by 3 so it is composite. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1, 2, and 0. 1, 2, and 0 have a different name.
No.
No.
No. it is composite. 57 is divisible by 3 and 19 :)
57 is divisible by 1, 3, 19 and 57.
Yes, 57/3 = 19
No. 57 is not evenly divisible by six.
1, 3, 19, 57.