57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
No.
No.
Any of its multiples! Simply calculate any of the following: 57 x 0 57 x 1 57 x 2 57 x 3 57 x (-1) 57 x (-2) etc., and you get a number that is a multiple of 57, and therefore, divisible by 57.
Sadly, it is not.
The factors of 27 are: 1, 3, 9, 27 The factors of 57 are: 1, 3, 19, 57 The factors of 97 are: 1, 97 The factors of 98 are: 1, 2, 7, 14, 49, 98
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
To determine what 171 is divisible by, we need to find its factors. The factors of 171 are 1, 3, 9, 19, 57, and 171. Therefore, 171 is divisible by 1, 3, 9, 19, 57, and 171.
No. 57 is divisible by 3.
1, 3, 19, 57.
No.
No.
57 is divisible by 3 so it is composite. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1, 2, and 0. 1, 2, and 0 have a different name.
No. it is composite. 57 is divisible by 3 and 19 :)
57 is divisible by 1, 3, 19 and 57.
Yes, 57/3 = 19
No. 57 is not evenly divisible by six.