Q: What factors are divisible by 57?

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57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.

No.

No.

Any of its multiples! Simply calculate any of the following: 57 x 0 57 x 1 57 x 2 57 x 3 57 x (-1) 57 x (-2) etc., and you get a number that is a multiple of 57, and therefore, divisible by 57.

Sadly, it is not.

Related questions

The factors of 27 are: 1, 3, 9, 27 The factors of 57 are: 1, 3, 19, 57 The factors of 97 are: 1, 97 The factors of 98 are: 1, 2, 7, 14, 49, 98

57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.

No. 57 is divisible by 3.

1, 3, 19, 57.

57 is divisible by 3 so it is composite. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1, 2, and 0. 1, 2, and 0 have a different name.

No.

No.

No. it is composite. 57 is divisible by 3 and 19 :)

57 is divisible by 1, 3, 19 and 57.

Yes, 57/3 = 19

No. 57 is not evenly divisible by six.

1, 3, 19, 57.