Both 57 and 9 are divisible by 3. So, 19/3 would be 57/9 in it's most reduced form.
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
The numbers that are divisible by 57 are infinite. The first four are: 57, 114, 171, 228 . . .
3, yes. All the rest, no.
No. 1,197 is divisible by these numbers: 1, 3, 7, 9, 19, 21, 57, 63, 133, 171, 399, 1197.
3 yes, 9 no.
9
Both 57 and 9 are divisible by 3. So, 19/3 would be 57/9 in it's most reduced form.
Yes because 513/9 = 57
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
The numbers that are divisible by 57 are infinite. The first four are: 57, 114, 171, 228 . . .
3, 9, 19, 57, 171, 361, 1083.
No. 57 is divisible by 3.
3, yes. All the rest, no.
1, 3, 19, 57.
No. 1,197 is divisible by these numbers: 1, 3, 7, 9, 19, 21, 57, 63, 133, 171, 399, 1197.
No.