Both 57 and 9 are divisible by 3. So, 19/3 would be 57/9 in it's most reduced form.
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
The numbers that are divisible by 57 are infinite. The first four are: 57, 114, 171, 228 . . .
3, yes. All the rest, no.
No. 1,197 is divisible by these numbers: 1, 3, 7, 9, 19, 21, 57, 63, 133, 171, 399, 1197.
3 yes, 9 no.
9
Both 57 and 9 are divisible by 3. So, 19/3 would be 57/9 in it's most reduced form.
Yes because 513/9 = 57
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
The numbers that are divisible by 57 are infinite. The first four are: 57, 114, 171, 228 . . .
3, 9, 19, 57, 171, 361, 1083.
No. 57 is divisible by 3.
3, yes. All the rest, no.
1, 3, 19, 57.
No. 1,197 is divisible by these numbers: 1, 3, 7, 9, 19, 21, 57, 63, 133, 171, 399, 1197.
To determine what 171 is divisible by, we need to find its factors. The factors of 171 are 1, 3, 9, 19, 57, and 171. Therefore, 171 is divisible by 1, 3, 9, 19, 57, and 171.