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I'm guessing you want to solve for t so: 3t-6=t-2 u bring the t from the left side and subtract it from the 3t and u get 2t b/c 3-1 is 2 2t-6=2 then u bring the 6 over to the right side and u add it to the 2 and u get 2t=8 and then u divide 8 by 2 and u get t=4 if u dont understand u shud probably go to an algebra teacher because they can explain it better
you would get the letter t
you are saying t + t + t + 3t = 6 + 4t if soo.. you must combine like terms... meaning combine all the "t's" on the left hand side of the equal side. when you add the "t's" together... you will get "6t" so now your problem will look like this: 6t = 6 + 4t since you want "t" by itself... you must bring over the positive "4t" to the left hand side. To do that you must subtract 4t to both sides. so it should look like this: 2t = 6 from there you must divide 2 to both side of the equation cause you want "t" by itself. when you do that... your answer will be t = 3
If the question is asking, "How far will the private plane fly before the jet overtakes it ?" Both planes will have flown the same distance. Distance = Time (T) x Velocity. Therefore 192 x T = 960(T - 2) = 960T - 1920 768T = 1920 : T = 2.5 In 2.5 hours the private plane flies 192 x 2.5 = 480 miles. (The jet plane in 0.5 hours flies 960 x 1/2 = 480 miles)
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