16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4
t with a small 4 to the top right of it
Neither, it is a power sequence. t(n) = n4 so t(6) would be 64 = 1296
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
In DNA, there are 4 different kinds of nucleotides. A, T, C and G In RNA, there are also 4, but T has been replaced by U. (I think. It's been awhile) So there are 81 combos that you might see in real life, but there are 243 that you could prepare in a lab.
t^4 - 81 = (t^2)^2 - (3^2)^2 = (t^2 - 3^2)(t^2 + 3^2) = (t - 3)(t + 3)(t^2 + 9)
81.
16t(t + 4) is the factorization Usually it's set = to 0 16t (t+4) =0 So, either 16t = 0 or t + 4 = 0 t = 0 or t = -4
T to the fourth power is already fully simplified unless you have a value for "t."
You can take a 5s2t out of all of that, leaving yourself with 3s4t3 + 19s3t2 + 7s2t4 - 7
t with a small 4 to the top right of it
1
The prime factorization for 68 is: 2 x 2 x 17
(t - 3)(t + 3)(t2 + 9)
Irving Layton died on January 4, 2006 at the age of 93.
t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9) t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3) so the factors of t4-81 are :(t2+9)(t+3)(t-3) Hope this helps :-) I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)
Neither, it is a power sequence. t(n) = n4 so t(6) would be 64 = 1296