Lots of them, for example:
eiθ = cos θ + i sin θ
The quadratic formula when b2 < 4ac (eg x2 + x + 1 = 0), then the solutions are:
x = (-b ± i √(4ac - b2)) ÷ 2
VRMS = 1/N times square root of [ sum(Vn2) ]
The square root of 1 is 1.The square root of 0 is 0.
The square root of 1 is just 1
xn+1 = 1/2 ( xn + N/xn )
The answer will depend on how far the square root sign goes.If you want to solve for "x", I suggest you isolate the square root on the left (if it only covers the "2x" part, move the "1" to the other side of the equation). Then, if you square both sides of the equation, you get a formula which you can easily convert to a form which can be solved with the quadratic equation.
To find the square root of a quarter, you can use the formula for square roots. The square root of a number x is a number that, when multiplied by itself, gives x. In this case, the square root of 1/4 (a quarter) is 1/2, because (1/2) * (1/2) = 1/4. Therefore, the square root of a quarter is 1/2.
VRMS = 1/N times square root of [ sum(Vn2) ]
There is no formula relating to a perfect square but if you want a method 1. Find square root(x) 2. Take the integer component (integral value) of square root(x) 3 Add 1 to intenger(square root(x)) 4. square it So: (integer(square root(x)) + 1)^2
0
The square root of 1/9 is 1/3 because the square root of 1 is 1 and the square root of 9 is 3.
Square root of 1/2 = (1)/(square root of 2) = 1/1.4142 = 0.7071 Also Square root of 1/2 = Square root of 0.5 = 0.7071
square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
x2+2x=9 we can complete the square or use the quadratic formula. Let's complete the square. add 2/2=1 to both sides and we ahve x2+2x+1=10 now factor the left side and use the square root property (x+1)2=10 so x+1= plus of minus the square root of 10 x=- 1+ or - square root of 10 using the quadratic formula we have a=1, b=2 and c=-9 so [-2+ or - (square root of (4+36))]/2= -1 + or - square root of 10 as we had before.
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
Same Square root of 1 is 1
the square root of 1 is 1. The square root of -1 is j (if you are an engineer) or i (if you are a math geek)
The square root of 1 is 1.The square root of 0 is 0.