Lots of them, for example:
eiθ = cos θ + i sin θ
The quadratic formula when b2 < 4ac (eg x2 + x + 1 = 0), then the solutions are:
x = (-b ± i √(4ac - b2)) ÷ 2
VRMS = 1/N times square root of [ sum(Vn2) ]
Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.
The square root of 1 is 1.The square root of 0 is 0.
xn+1 = 1/2 ( xn + N/xn )
The square root of 1 is just 1
To find the square root of a quarter, you can use the formula for square roots. The square root of a number x is a number that, when multiplied by itself, gives x. In this case, the square root of 1/4 (a quarter) is 1/2, because (1/2) * (1/2) = 1/4. Therefore, the square root of a quarter is 1/2.
VRMS = 1/N times square root of [ sum(Vn2) ]
There is no formula relating to a perfect square but if you want a method 1. Find square root(x) 2. Take the integer component (integral value) of square root(x) 3 Add 1 to intenger(square root(x)) 4. square it So: (integer(square root(x)) + 1)^2
Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.
0
The square root of 1/9 is 1/3 because the square root of 1 is 1 and the square root of 9 is 3.
Square root of 1/2 = (1)/(square root of 2) = 1/1.4142 = 0.7071 Also Square root of 1/2 = Square root of 0.5 = 0.7071
x2+2x=9 we can complete the square or use the quadratic formula. Let's complete the square. add 2/2=1 to both sides and we ahve x2+2x+1=10 now factor the left side and use the square root property (x+1)2=10 so x+1= plus of minus the square root of 10 x=- 1+ or - square root of 10 using the quadratic formula we have a=1, b=2 and c=-9 so [-2+ or - (square root of (4+36))]/2= -1 + or - square root of 10 as we had before.
square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
Same Square root of 1 is 1
the square root of 1 is 1. The square root of -1 is j (if you are an engineer) or i (if you are a math geek)