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x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
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Let A equals 1 plus 2i and let C equals 5 plus 5i what is A-C?
-4-3i
Solve by factoring 3x2 equals -9?
3x2 = -9 (divide both sides by 3) x2 = -3 (x would have to be the square root of -3) x = ±√-3 x = ±√3i Since you want to solve by factoring: x2 = -3 add 3 to both sides x2 + 3 = 0 x2 - 3i2 = 0 x2 - (√3i)2 = 0 Factor: (x - √3i)(x + √3i) = 0 x - √3i = 0 or x + √3i = 0 x = √3i or x = -√3i
What is the answer if you Find all the roots of the equation x4 - 2x3 plus 14x2 - 18x plus 45 0 given that 1 plus 2i is one of its roots.?
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
What is conjugate of 2 plus 3i?
- 2 - 3i
8 plus 6i-2 plus 3i?
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
If one of the roots of the quadratic equation is 1 plus 3i what is the other root?
The answer to the question, as stated, is that the other root could be anything. However, if all the coefficients of the quadratic equation are real numbers, then the other root is 1 minus 3i.
What is the conjugate of -2 plus 3i?
-2 - 3i
What is the complex conjugate of 2 plus 3i?
[ 2 - 3i ] is.
What is the reciprocal of 1 plus 3i?
1/(1+ 3i)
What is the answer to x2 equals -9?
11
Find the sum of negative 2 plus 3i and negative1 minus 2i?
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
What is the factor of x2 plus 9?
x2 + 9 has no real factors. Its complex factors are (x + 3i) and (x - 3i) where i is the imaginary square root of -1.
