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Well, 47 49 51 53 are four consecutive odd numbers those total squared has for identical digits. 40000.... The square root of any number that is only four digits long all containing the same digit has a value that is not an integer.
There is no set of four consecutive numbers with a product of 182. There is a set of four consecutive numbers with a sumof 182: 9, 20, 21 and 22.
If the range is three, then there are four whole numbers involved. The average value of these numbers is 66/4 = 16.5. Because the numbers are consecutive - evenly distributed - 16.5 is actually 'in the middle' of the four. From which we can infer that the numbers in question are 15,16,17 and 18.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
The four consecutive natural numbers whose sum is 214 are 52, 53, 54 and 55.