IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
44 and 45 75 and 76 98 and 99
49 and 98
100
The factor pairs of 98 are: 1 × 98 2 × 49 7 × 14
97, 98, 99 and 100.
44 and 45 75 and 76 98 and 99
There aren't four consecutive whole numbers that total 96. 22, 23, 24 and 25 total 94 23, 24, 25 and 26 total 98
The prime numbers (factors) of 98 are: 2 and 7
25 and 98 are not prime numbers
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
Opposite numbers are numbers such that their sum is equal to 0 So the opposite number of -98 is 98
The two whole numbers that can go into 98 are 1, 2, 7, 49, and 98.
The numbers are 98 and 64
Let the first number = xThe four consecutive numbers will be x, (x+1), (x+2), and (x+3).Add them, and set the result = to 398.eg.x + x + 1 + x + 2 + x + 3 = 3984x + 6 = 398Then use algebra to solve for x.4x = 392x=98This is the first number. The following numbers can be obtained by substituting 98 for x in the above sequence. This will give you the numbers. 98, 99, 100, and 101. You will find that if you add them together, they will equal 398.Four consecutive numbers of 398 would be divided into two groups, those before 398 and those after 398.In the first group, that is those numbers before 398 would be:394, 395, 396 and 397.In the second group, that is those numbers after 398 would be:399, 400, 401 and 402.The numbers are 98, 99, 100 and 101.
44 and 45 75 and 76 98 and 99
49 and 98