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Let the first number = x
The four consecutive numbers will be x, (x+1), (x+2), and (x+3).
Add them, and set the result = to 398.
eg.
x + x + 1 + x + 2 + x + 3 = 398
4x + 6 = 398
Then use algebra to solve for x.
4x = 392
x=98
This is the first number. The following numbers can be obtained by substituting 98 for x in the above sequence. This will give you the numbers. 98, 99, 100, and 101. You will find that if you add them together, they will equal 398.
Four consecutive numbers of 398 would be divided into two groups, those before 398 and those after 398.
In the first group, that is those numbers before 398 would be:
394, 395, 396 and 397.
In the second group, that is those numbers after 398 would be:
399, 400, 401 and 402.
The numbers are 98, 99, 100 and 101.
What else can I help you with?
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