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To determine the fraction of children that should be homozygous smooth, we need to know the genetic information regarding the traits involved, specifically the alleles for smooth and rough phenotypes. If we assume that smooth is a dominant trait (S) and rough is recessive (s), we can use a Punnett square based on the parental genotypes. Without specific parental genotypes provided, it’s impossible to calculate the exact fraction; however, if both parents are heterozygous (Ss), then 1/4 of the offspring would be expected to be homozygous smooth (SS).
What else can I help you with?
What is a fraction that can be graphed with a line or smooth curve?
A fraction is a single value. At is neither a graph nor a curve.
Why do the equipotential lines not form a smooth line or curve?
I am not sure what situation you are talking about; usually such curves should be smooth.
Should you disregard a data point if it is way of the trend line?
If you know the data should be smooth, then yes. But if there are sharp resonances you could miss such things altogether.
When graphing why should you draw a smooth line that reflects the general patter rather that automatically connect the data points?
It is not true to say that you should automatically draw a smooth line. It depends on what you are attempting to do. A smooth line may be a good indicator of a trend but such a line is useless if you want to find out whether or not there is any periodicity in the data. For the latter you must join the data points and look for periodic patterns.
What are the key considerations for the Integration Process?
You need to consider all of the key players. You should figure out how to make the start as smooth as possible.
How could a guinea pig breeder whether a rough-coated guinea pig is homozygous or heteorzygous for this trait?
A breeder could determine if a rough-coated guinea pig is homozygous or heterozygous by conducting a test mating. Breeding the rough-coated guinea pig with a smooth-coated guinea pig would show if the rough coat is dominant or recessive. If all the offspring have rough coats, it indicates the rough-coated guinea pig is homozygous for the trait. If both rough and smooth-coated offspring are produced, then the rough-coated guinea pig is heterozygous.
What is a fraction that can be graphed with a line or smooth curve?
A fraction is a single value. At is neither a graph nor a curve.
Smooth coat is dominant to wire coat in terriers If you have a smooth coated terrier How can you determine if your terrier is a carrier for wire coat or is homozygous for smooth coat?
You would have to breed it to a wire coat ( W_ x ww ) and if there are any puppies born with a wire coat then you know that your smooth coat carries the recessive gene.
Smooth coat is dominant to wire coat in terriers. You have a smooth coated terrier. How can you determine if your terrier is a carrier for wire coat or is homozygous for smooth coat?
You would have to breed it to a wire coat ( W_ x ww ) and if there are any puppies born with a wire coat then you know that your smooth coat carries the recessive gene.
How many genotypes are there for the smooth pod phenotype?
The smooth pod phenotype in pea plants is typically associated with a specific gene controlled by a single locus with two alleles: one for smooth pods (dominant) and one for wrinkled pods (recessive). The possible genotypes for the smooth pod phenotype are homozygous dominant (SS) and heterozygous (Ss). Therefore, there are two genotypes that can express the smooth pod phenotype.
In dogs wire hair S is dominant to smooth s In a cross of a homozygous wire-haired dog with a smooth-haired dog what will be the phenotype of the F1 generation?
All the F1 will have wire hair.The reason:A homozygous wire-haired dog must be SS. It must have at least one S allele if it shows the dominant character, and "homozygous" means pure-breeding, so there is no other allele present.A smooth-haired dog must be ss. Any organism displaying a recessive trait must be homozygous, as a dominant allele would mask the recessive one.So the cross is:SS x ssand one parent must pass on the S gene, one the s. Therefore all the F1 must be Ss. Their phenotype is wire-haired, because they have a dominant allele, but they are all heterozygous, because they inherited a recessive gene from the smooth-haired parent.This cross demonstrates Mendel's First Law.
How do you softenend cream cheese?
first you should help your self get smooth then you should think of getting a cheese getting smooth
Does the specs on the rear rotor of the 2003 pt cruiser have factory groves for the pads?
The rotors should be smooth, no grooves where the pads touch.The rotors should be smooth, no grooves where the pads touch.
Should a runway be made smooth or rough?
A runway must be smooth in order for an airplane to land safely on it.
What helps DoDDS-K plan a smooth transition for school aged children?
DoDDS utilizes school liaison officers in order to facilitate a smooth transition for school-aged children. DoDDS stands for the Department of Defense Dependents Schools.
What should the consistency of a risotto be like?
smooth and creamy
Why do the equipotential lines not form a smooth line or curve?
I am not sure what situation you are talking about; usually such curves should be smooth.
