That polygon is called a "triangle". It has no diagonals.
There are: 0.5*(1002-(3*100)) = 4850 diagonals
n(n-3)/2
A polygon with n sides had n*(n-3)/2 diagonals. So a 20 sided polygon would have 20*17/3 = 170
The formula for determining the number of diagonals in a shape is n(n-3)/2 where n=vertices, (corners or intersections of geometric shapes). For an eight sided shape we replace n with 8. 8(8-3)/2 8(5)/2 (8x5)/2 40/2=20 An octagon contains 20 diagonals. For a further example we can determine the diagonals in a shape with 5 sides: 5(5-3)/2 5(2)/2 (5x2)/2 10/2=5 A Pentagon contains 5 diagonals.
A geometrical triangle has 3 sides but no diagonals.
That polygon is called a "triangle". It has no diagonals.
A polygon with n sides has n(n-3)/2 diagonals. A heptagon has 7 sides giving it 7(7-3)/2 = 14 diagonals.
There are: 0.5*(1002-(3*100)) = 4850 diagonals
It must have 19 sides to comply with the formula:- 0.5*(192-(3*19)) = 152 diagonals
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
There are 7*(7-3)/2 = 7*4/2 = 14 diagonals.
n(n-3)/2
5(5-3)/2. That it is the formula so that shape would have 5 diagonals. n(n-3)/2 where n is the number of sides
A polygon with n sides had n*(n-3)/2 diagonals. So a 20 sided polygon would have 20*17/3 = 170
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
A polygon with n sides has 1/2*n*(n - 3) diagonals. So, for a polygon, with n = 12, there are 54 diagonals.