There is no such shape. And unfortunately the word is too much like two terms to determine which of them you mean.If the polygon has n sides (n>3), then it has n*(n-3)/2 diagonals.
A regular 100-sided polygon has 4,850 diagonals. You can either check this for yourself, or use the formula provided in Related Questions below.
100*(100-3)/2 = 4850
It has: 0.5*(100^2-(3*100)) = 4850 diagonals
It consists of 98 triangles and has 4850 diagonals
100 sided polygon has = n(n-3)/2 diagonals = 100(100-3)/2 = 4850 diagonals
There is no such shape. And unfortunately the word is too much like two terms to determine which of them you mean.If the polygon has n sides (n>3), then it has n*(n-3)/2 diagonals.
0.5*(1002-300) = 4850 diagonals
A regular 100-sided polygon has 4,850 diagonals. You can either check this for yourself, or use the formula provided in Related Questions below.
100*(100-3)/2 = 4850
100 diagonals * * * * * No, it is 0.5*10*(10-3) = 35
It has: 0.5*(100^2-(3*100)) = 4850 diagonals
It consists of 98 triangles and has 4850 diagonals
A polygon with 1000 sides is still a polygon but even a polygon of 100 sides gives characteristics of a circle. When demonstrating circles a polygon of 100 sides helps show the circle characteristics.
1oo diagonals, because 1 side has 10 diagonals so 10 sides (10x10) = 100 diagonals! This is the correct answer..... a decagon has 35 diagonals. The equation for the this is D=n(n-3)/2 meaning diagonals = number of sides (N) multiplied by number of sides minus 3. and that number over 2. D=10(10-3)/2
98
i think it is a 100 - polygon