y=x^3
The slope of the line that represents the graph of that equation is 15.
A linear graph is a model of a straight line on the X and Y axis. It represents the equation y=mx+b. A liner graph has a slope. A liner graph cannot be equaled to 0.
The is a straight line parallel to the y-axis with an x intercept at -3.
If there is one equation that can be solved, then (x-2)2 + (y-3)2 = 0 For an equation such as x+y-5 = 0 you will have an infinity of solutions unless you add another, independent equation and solve them simultaneously.
The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?
To graph the equation y-x=3, first rearrange it in slope-intercept form by isolating y: y=x+3. This equation represents a line with a slope of 1 and y-intercept of 3. You can plot the y-intercept at (0,3) then use the slope to find another point and draw a straight line connecting the two points.
yx-3 is not an equation, and it has no graph.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
y=x^3
Assuming the graph is: x = - 305 y, then the y intercept is at y = 0Assuming the graph is: x - 3 = 5y, then the y intercept is at y = -3/5The main point for you to realize here is that a graph represents an equation,and " -305y " is not an equation. So some kind of assumption has to be madein order to come up with something that can be graphed.
The slope of the line that represents the graph of that equation is 15.
A linear graph is a model of a straight line on the X and Y axis. It represents the equation y=mx+b. A liner graph has a slope. A liner graph cannot be equaled to 0.
The is a straight line parallel to the y-axis with an x intercept at -3.
If there is one equation that can be solved, then (x-2)2 + (y-3)2 = 0 For an equation such as x+y-5 = 0 you will have an infinity of solutions unless you add another, independent equation and solve them simultaneously.
False. X = 3 is a vertical line.
To graph the equation y - x + 3, we can first rearrange it into slope-intercept form, y = x - 3. This equation represents a line with a slope of 1 and a y-intercept of -3. To graph it, start by plotting the y-intercept at (0, -3), then use the slope to find another point, such as moving up 1 unit and to the right 1 unit. Connect these points with a straight line to complete the graph.