0.666 ^^^^ his answer mine 3 in 8 i believe. which is 0.375 you can get h,h,h h,t,h h,t,t h,h,t t,h,h t,t,h t,h,t t,t,t the ones you are looking for are h,h,t t,h,h h,t,h
There are 8 permutations of three coins ... T T T T T H T H T T H H H T T H T H H H T H H H ... counting heads and sorting by count, you get ... 0 - T T T 1 - T T H 1 - T H T 1 - H T T 2 - T H H 2 - H T H 2 - H H T 3 - H H H ... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.
4 : Each coin toss multiplies the generated outcome by two. The outcome for two tosses can be Heads (H) Tails (T), H H, T T or T H. As such, with three tosses the outcome can be H H H, H H T, H T H, T H H, T T H, T T T, T H T, H T T. We can define the number of outcomes as 2^n, where n is the amount of tosses.
4: h/h, h/t, t/h & t/t
There is no simple formula to determine the half life of every single radioactive isotope. However, y = A(.5)^t/h, where A=staring amount, t=time, and h= half life, is a general equation that usually works well.
h(t)= -g*t^2 + V*t +h where h(t) is the periodic time, t is the overall time, V is the initial velocity, h is the initial hieght, and g is the gravitational constant either 16 or 4.9. This equation will trace the path taken by a projected object.
The change in entropy between products and reactants in a reaction.
The change in entropy between products and reactants in a reaction.
T = 101.3 eH/26,200eH/26,200 = T / 101.3H/26,200 = ln(T/101.3)H = 26,200 ln(T/101.3)
The change in entropy between products and reactants in a reaction.
1 2 3 4 h h h h h h h t h h t h h h t t h t h h h t h t h t t h h t t t t h h h t h h t t h t h t h t t t t h h t t h t t t t h t t t t
Thats a simple question it gets higher...
The change in enthalpy between products and reactants in a reaction
4 coins tossed could have the following patterns T T T T T T T H, T T H T, T H T T, H T T T T T H H, T H T H, T H H T, H H T T, H T H T, H T T H H H H T, H H T H, H T H H, T H H H H H H H Odds of 2H&2T = 6/16 = .375
The change in entropy between products and reactants in a reaction.
Well the equation is: 6CO2 + 6H2O + -s-u-n-l-i-g-h-t--> C6H12O6 + 6O2.
The equation for ∆G is ∆G = ∆H - T∆S H is enthalpy and S is entropySo, ∆G is negative if T∆S is greater than ∆H