Suppose "a" is the length of the side of a square.
Area of the square = axa = a2
Now if we double the sides then the length of each side will be "2a".
The area of the square with doubled side = "2ax2a" = 4a2 or 4 times the previous value.
If you need further help in maths and other science subjects then you can get an online tutor @ https://tutstu.com Here you can register for free and find tutors for various subjects fitting your preferences.
No, it will be quadrupled.
The area gets doubled.
If the altitude is not changed, the area would be doubled.
The area increases as the square of the radius (or diameter). So if you double the radius you * 4 (quadruple) the area. Treble the radius, you *9 the area.
If the linear dimensions are doubled, the area is multiplied by (2)2 = 4 .
four times the initial value
No, it will be quadrupled.
The area gets doubled.
When the diameter is doubled, perhaps? Then the area is 4 x larger.
the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...
If the altitude is not changed, the area would be doubled.
Area = length*width new Area = 2 * length * width Area is doubled
The area increases as the square of the radius (or diameter). So if you double the radius you * 4 (quadruple) the area. Treble the radius, you *9 the area.
Refer to the question. It says the base is doubled! And when the dimensions of the base are doubled, the area is multiplied by 4.
The Area of a square can be written as it's side length^2, orA = s^2if the side length is doubled, then s' is 2s.A' = (s')^2A' = (2s)^2A' = 4s^2 = 4*AWhen the side length is doubled, the area increases by a factor of 4
If the linear dimensions are doubled, the area is multiplied by (2)2 = 4 .
It quadruples.