The Area of a square can be written as it's side length^2, or
A = s^2
if the side length is doubled, then s' is 2s.
A' = (s')^2
A' = (2s)^2
A' = 4s^2 = 4*A
When the side length is doubled, the area increases by a factor of 4
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When the length of a square is doubled, the area is quadrupled. This is because the area of a square is calculated by multiplying the length by the width, and if both the length and width are doubled, the resulting area is four times the original. Mathematically, if the original area of the square is A, then the new area would be 4A after doubling the length.
the area should double also Answer 2 The area will quadruple. Imagine a square with sides 1 x 1. If you doubled the length of the sides you'd have a square of 2 x 2. You'd be able to get four 1 x 1 squares inside that.
A=L(squared) (for a square only) Lets say our original square is L=2 then area is A=4 so if we double the Area A=8 then l=? L=square root of 8 therefor what ever your area is the Length of each side is the square root of the Area (on the first problem) square root of 4 is 2 therefor L is 2 Makes sence?
Area = Length * Length Area = Length2 Length = Area Length = 230 Length = 15.16575..... -Oliver Crow
The length of a square with an area of 81 would be 9.
The length and width of a square by definition are of equal length. The area (A) of a square = d2, where d is the length of one side. If the area is known, then the length of the side of a square, d = √A (square root of A).