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A Fiber has a length of atleast 100 times its diameter or width. and its length must be atleast 0.2 in (0.5 cm)

Q: What has a length at least 100 times its width?

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Area = length times width A = LW 100 m^2 = L(11 m) = 9.090909091

If you're talking about a rectangle, then the answer is 100. There are 2 sides that have 40 as the length, and double that length is 80. There are 2 sides that have 10 as the width, and double that width is 20. 80 + 20 = 100.

100 metres by 100 metres

All that can definitely be said is that length plus width = 50 feet.

20

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Area = length times width A = LW 100 m^2 = L(11 m) = 9.090909091

the length of a rectangular garden is 2 feet longer than 3 times it's width .if the perimeter of the garden is 100 feet find the width and length of the garden

Volume is determined by length times width times heights (LxWxH). So the volume of this object which I assume to be a cube is 5 times 5 times 4 which equals 100.

Length + width = half perimeter = 100". Length is 98", width is 2"

If you're talking about a rectangle, then the answer is 100. There are 2 sides that have 40 as the length, and double that length is 80. There are 2 sides that have 10 as the width, and double that width is 20. 80 + 20 = 100.

im not 100% sure but i think you multiply length times width

1 m = 100 cm multiply length*width*height and divide that answer by 100

100 metres by 100 metres

It is 4,000 times 100 = 400,000 square meters or 4 times 0.1 = 0.4 square km

If the area is of a rectangle, it is simply the length times the width. If you have a rectangle with sides of 2 and 50 then the area is 100.

The length is 100 / 12.5 = 8 meters.

A square of area 100 cm squared, has the dimensions 10 X 10(length X Width or four sides of length ten).The perimeter is equal to length of sides times number of sides.Perimeter:10 times 4=40cm